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Second quantization operators

  1. Mar 3, 2014 #1
    I have a doubt on the second quantization formalism. Suppose that we have two spin-1/2 fermions which can have just two possible quantum number, 1 and 2. Consider the wave function:
    $$
    \psi(r_1,r_2)=\frac{1}{\sqrt{2}}\left(\psi_1(r_1)\psi_2(r_2)-\psi_1(r_2)\psi_2(r_1)\right).
    $$
    The second quantized field is defined as:
    $$
    \Psi(r)=\sum_{k=1}^2a_k\psi_k(r),
    $$
    where [itex]a_k[/itex] are the annihilation operators for fermions, i.e. anti-commuting with each other.

    What's the action of [itex]\Psi(r)[/itex] on the wave function [itex]\psi(r_1,r_2)[/itex]?
     
  2. jcsd
  3. Mar 3, 2014 #2

    Bill_K

    User Avatar
    Science Advisor

    In second quantization, the field operator doesn't act on a wavefunction at all, it acts on an abstract state vector in Fock space.

    Be careful to keep straight the meaning of the subscripts in the two examples. In your first-quantized wavefunction, the subscripts refer to particle 1 or particle 2. But in the expression for the second-quantized field operator, the subscript k is used to indicate a single-particle state, not a particle.
     
  4. Mar 3, 2014 #3
    Got it! Thank you
     
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