1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Seem reasonable?

  1. Apr 28, 2008 #1

    bcjochim07

    User Avatar

    1. The problem statement, all variables and given/known data
    A nebula-- a region of the galaxy where new stars are forming contains a very tenuous gas with 100 atoms/ cm^3. This gas is heated to 7500 K by the uv radiation from nearby stars. What's the gas pressure in atm?


    2. Relevant equations



    3. The attempt at a solution

    100 atoms * 1mol/6.022*10^23 atoms = 1.02 * 10^-16 moles
    1 cm^3 * (1m/100cm)^3 = 1 * 10^-6 m^3
    R= 8.31 J/mol K
    pV=nRT
    p(10^-6 m^3) = (1.02 * 10^-16 mol)(8.31)(7500 K)
    p= 1.03 * 10 ^-11 Pa = 1.02 * 10 -16 atm Does this seem too small to you?
     
    bcjochim07, Apr 28, 2008
  2. jcsd
    Phys.org - latest science and technology news stories on Phys.org
  3. Apr 28, 2008 #2

    dynamicsolo

    User Avatar
    Homework Helper

    How did you divide 100 by Avogadro's number and get 10^-16?

    We are talking about interstellar space here. The pressure is going to be very low...

    Here's a check you can do. The molar volume of an ideal gas at STP (about 300 K) is 22.4 liters, so there is roughly 0.05 mole/L or 5 x 10^-5 mole/cc . This is 25 times hotter, so that would lower the number of moles by a factor of 25, which would be 2 x 10^-6 mole/cc ; that's still at 1 atmosphere. How many atoms are in the one c.c. at this point?

    If you reduce the number of atoms to 100, what does the pressure become? That will give you the order of magnitude (and maybe one sig-fig) of the pressure.

    EDIT: That suggests that your answer is OK, but you mistyped your number of moles...
     
    Last edited: Apr 28, 2008
    dynamicsolo, Apr 28, 2008
  4. Apr 28, 2008 #3

    bcjochim07

    User Avatar

    oops it should be the 1.66 * 10 ^ -22, that was the answer I typed in as moles. I came up with the answer correctly though. Other than that it looks fine?
     
    bcjochim07, Apr 28, 2008
  5. Apr 28, 2008 #4

    dynamicsolo

    User Avatar
    Homework Helper

    The check I describe confirms your result. So it seems to be just fine...
     
    dynamicsolo, Apr 28, 2008
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Seem reasonable?

  1. Is it reasonable? (Replies: 4)

  2. Seemingly simple (Replies: 1)

  3. A reasonning question (Replies: 1)

  4. Reasoning behind? (Replies: 2)

  5. Equilibrium Reasoning (Replies: 2)

Loading...