What is the actual solution to the following supposed paradox? I haven't been able to put my finger on it yet. --- The Twins Doppler Paradox: The following is based upon the axiom that during a specific interval of emission time, a laser beam or some other cohesive reliable source of a given wavelength/frequency will emit a certain number of waves. If that light is doppler shifted, the number of total waves will not change so consequently, the interval of viewing time will be shortened for blue shift and lengthened for red shift in consideration of the constancy of light speed. In the twins paradox, let us have both twins shining identical lasers at eachother at some exact known wavelength/frequncy. Now, we know for sure that the travelling twin has the slower clock because of acceleration. Lets examine what he sees on his outbound trip given the following test: The earth twin emits a light for 10 minutes at a frequency of 1000 waves/peaks/beats per minute. The travelling twin is moving at a speed close enough to light to cause his time to move at one tenth the time of the earth's. 1) Because he is moving away at some speed close to C he must see a redshifted beam of light that lasts longer than 10 minutes. 2) Because his time is much slower he must see a signal that beats 10,000 times in one of his minutes and is therefore blue-shifted and lasts 1 minute. These considerations bring up questions such as: Did the Milky way galaxy get accelerated away from the andromeda galaxy at nearly light speed some time billions of years ago? Are we moving towards or away from Andromeda? Now use the same circumstances as above except that both twins spend 10 minutes with light on and 10 with it off and repeat this cycle 10 times. Additionally, the travelling twin is now earthbound. In this example we observe the earth twin's perspective. 1) Because the earth twin's time goes so much faster, ten of the travelling twin's minutes lasts 100 of the earth twin's yet the same number of beats will be released from the traveller during that 100 minutes of earth time that would be released from the earth twin's identical laser during only 10 minutes, so the earth twin must see an extremely redshifted signal from the traveller. 2) Because he is traveling towards earth, we know there must be a blue shift for the earth twin observer. 3)If, for earth time, the traveller should only be releasing 100 beats per earth minute, and earth twin sees a blue shifted signal that equates to greater than 1000 beats per minute, earth will see far into the traveller's future. The earth observer twin will see the end of the traveller's 10th burst before 200 minutes. However we know that in 200 minutes of earth time he has only aged 20 minutes. He's only been able to push the button to turn the on laser one time. NOTE: The beginning and ending location as well as the travel time of the beam can be ignored because the phenomena would result in seeing further and further into the future over time such as to overcome the travel time between emitter and observer given a large enough sample period.