A door, 2.30m high and 1.30m wide, has a mass of 13.0kg. A hinge 0.40m from the top and another hinge 0.40m from the bottom support half the doors weight. Assume the CM is at the geometrical centre of the door, and determine the horizontal and vertical force components exerted by each hinge on the door.(adsbygoogle = window.adsbygoogle || []).push({});

The trick with the horizontal forces...

think of breaking the bottom hinge, and there is no door frame. Which way would the bottom of the door swing? to the right, if you use the picture. If you break the top hinge but leave the bottom one in tact, then the top of the door would swing to the left. This means the x-force for the bottom points to the left and the x-force for the top points to the right...and they must be equal since the door doesn't swing at all. Use net force to analyze that.

How can i go from here?

This problem is giving me a hard time for some reason.

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# Homework Help: Seemingly easy physics problem

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