Problem: I have to find out the power that is required to set the balanced seesaw from equilibrium to an oscillation that changes direction in an inclination of 30°. I also have to know the power required to eventually stop that motion and bring the seesaw back to equilibrium. I have calculated the angular velocity at the equilibrium point (when dropped from 30°) to 0.88 rad/s. Answer to my first question ought to be that the power is the same that is required to set the seesaw in 0.88 rad/s, but I just can't see the equation. Moment of inertia for a seesaw = (1/12)mL^2 Many thanks for your time! Eemu from Gothenburg, Sweden.