Homework Help: Self induction

1. Jul 12, 2010

A 50.0mh inductor is connected to an ac voltage source of 24.0V.The current flowing in this circuit is 0.60A.The frequency of the voltage source is :
a)50Hz
b)60Hz
c)1.27*10^3 Hz

My Work so far ! :
f = w/2pi.

But here we have L , E and i.

Any help will be welcomed.

2. Jul 12, 2010

kuruman

You can do better than this. How will you bring in L, E and i? Think impedance.

3. Jul 12, 2010

So,impedance is : z=Lw = L*2pi*f ....

A guess , z = V/I = E/i !! but V(max)/I(max)

4. Jul 12, 2010

kuruman

If z = V/I, can you relate ω to V and I?

5. Jul 12, 2010

So is it , V/I=Lw then V/LI=w=2pi*f .

6. Jul 12, 2010

kuruman

Correct.

7. Jul 12, 2010