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Semi-empirical mass formula.

  1. Mar 4, 2009 #1
    1. The problem statement, all variables and given/known data

    Use the semi-empirical mass formula to show that when an even-even nucleus of large Z undergoes fission into two identical odd-even fragments energy will be liberated provided that the approximate condition:

    c1(A) + c2(Z²) + C3(A)^-5/12 > 0

    is satisfied and give values for the constants c1, c2 and c3.



    2. Relevant equations

    Semi-empirical mass formula


    3. The attempt at a solution

    Do I use an example of any atom which is even-even and two other atoms which are odd-even. Then put it into the semi-empirical mass formula and then what exactly do I need?
     
  2. jcsd
  3. Mar 4, 2009 #2
  4. Mar 4, 2009 #3

    Avodyne

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    Science Advisor

    No, you need to demonstrate that it's true for any even-even nucleus of large Z and A decaying into two identical odd-even fragments (so what would the Z and A values of each fragment be?).
     
  5. Mar 5, 2009 #4
    The N = odd and Z= even for both identical fragments. But how would this help me?
     
  6. Mar 5, 2009 #5
    I'm having problems with the same question.

    My thinking so far:

    Each of the new nuclei will have 1/2A and 1/2Z

    For energy to be released the binding energy of the intial nuclei must be greater than two times the binding energy for one of the resultant nuclei.

    The odd-even means that the last term of the semi-empirical mass formula is 0, for even-even if delta(Z,A) is 1

    I've tried setting this up as an inequality and rearranging but I can't see how an A^(-5/12) would be arrived at. Are there terms that can be neglected for a large Z or was that just in the question to show the SEMF would be accurate in this case?
     
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