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I am writing my senior thesis (I am an undergrad math major at UCSB) on Dirichlet Series, which are, in the classical sense, series of the form
where [tex]a_n,s\in\mathbb{C}[/tex] and [tex]a_n[/tex] is multiplicative, hence
I have begun this bit on analytic continuation for such series, here it goes:
so that
which is the first first stage of analytic continuation. Now, to the above series apply Euler's series transformation, which, if you don't recall, is
to get the the second stage, namely
when this same process of continuation is applied to the Riemann zeta it produces a series for the zeta function that converges for all s in the complex plane except s=1 (see prior thread for details.) My trouble is proving convergence in the present, more general case. Any thoughts?
[tex]\xi (s)=\sum_{n=1}^{\infty}\frac{a_n}{n^s}[/tex]
where [tex]a_n,s\in\mathbb{C}[/tex] and [tex]a_n[/tex] is multiplicative, hence
[tex]\forall n,m\in\mathbb{N}, \, a_{nm}=a_{n}a_{m}[/tex]
I have begun this bit on analytic continuation for such series, here it goes:
[tex]\xi (s)+\sum_{n=1}^{\infty}(-1)^{n}\frac{a_n}{n^s}=\sum_{n=1}^{\infty}\frac{a_n}{n^s}+\sum_{n=1}^{\infty}(-1)^{n}\frac{a_n}{n^s}=2\sum_{n=1}^{\infty}\frac{a_{2n}}{(2n)^s}=2^{1-s}a_2\sum_{n=1}^{\infty}\frac{a_n}{n^s}[/tex]
so that
[tex]\xi (s)=(1-a_22^{1-s})^{-1}\sum_{n=1}^{\infty}(-1)^{n-1}\frac{a_n}{n^s}[/tex]
which is the first first stage of analytic continuation. Now, to the above series apply Euler's series transformation, which, if you don't recall, is
[tex]\sum_{n=1}^{\infty}(-1)^{n-1}b_n=\sum_{n=0}^{\infty}\frac{1}{2^{n+1}}\sum_{m=0}^{n}(-1)^{m}\left( \begin{array}{c}n\\m\end{array}\right) b_{m+1}[/tex]
to get the the second stage, namely
[tex]\boxed{\xi (s)=(1-a_22^{1-s})^{-1}\sum_{n=0}^{\infty}\frac{1}{2^{n+1}}\sum_{m=0}^{n}(-1)^{m}\left( \begin{array}{c}n\\m\end{array}\right)\frac{a_{m+1}}{(m+1)^s}}[/tex]
when this same process of continuation is applied to the Riemann zeta it produces a series for the zeta function that converges for all s in the complex plane except s=1 (see prior thread for details.) My trouble is proving convergence in the present, more general case. Any thoughts?
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