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Using sentential calculus (with a four column format), prove that the conclusion (s ^ ~p) ==> t follows from the premises: ~(q ^ s) and q OR p. (Hint: Employ conditionalization).

Work done:

but, of course I'm to show (s ^ ~p) ==> t.Code (Text):

(1) ~(q ^ s) P

(2) (~q OR ~s) DeM (1)

(3) q OR p P

(4) p OR ~s Cut (2, 3)

(5) ~(s ^ ~p) DeM (4)

How should I go about it? thank you.

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# Sentential calculus q

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