- #1

Chandasouk

- 165

- 0

1) dy/dx = x

^{2}/y

ydy = x

^{2}dx

Integrate both sides and you get

y

^{2}/2 = x

^{3}/3 + C

My book gave 3y

^{2}- 2x

^{3}= C

2) dy/dx = x

^{2}/ y(1+x

^{3})

y(1+x

^{3})dy = x

^{2}dx

ydy = x

^{2}/(1+x

^{3}) dx

Integrating both sides, I got

y

^{2}/2 = 1/3*ln(1+x

^{3}) + C

but my book gave

3y

^{2}-2ln(1+x

^{3}) = C