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Separable Equations

  1. Oct 18, 2007 #1
    I am just supposed to find the general solution, in an explicit form if possible.

    y'=xcos^(2)y

    Thanks!
     
  2. jcsd
  3. Oct 18, 2007 #2
    Do your own HW.

    This problem can be answered by someone with a strong grasp of calculus I. Get your calculus I book out.

    Ken
     
  4. Oct 23, 2007 #3
    Multiply both sides by [tex]\sec^2{y}[/tex], to get

    [tex]y^{\prime} \sec^2{y} = x [/tex]

    Now, integrate both sides w.r.t. x to get

    [tex]\tan{y} = \frac{x^2}{2} + \kappa [/tex]

    where [tex]\kappa[/tex] is a constant.
     
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