1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Separation of variables.

  1. May 19, 2009 #1
    1. The problem statement, all variables and given/known data

    Hi, I dont really understand separation of variables very well, and I was hoping to do get my mind more clear on the following question:

    (Q) Use separation of variables to find all the separable solutions of the equation:

    d²y/dt² -c²(d²y/dx²) + w²y = 0

    where 'w' and c are constants.




    3. The attempt at a solution

    I first started by saying the solution to this equation can be written as:

    y = X(x)T(t)

    so: X(d²T/dt²) - c²(d²X/dx²)T + w²XT

    divide through by XT we get:

    (1/T)d²T/dt² -(c²/X)(d²X/dx²) + w² = 0

    What would be the next step? How can I find a solution from here?
     
  2. jcsd
  3. May 19, 2009 #2
    now you just have two independent DEQs to solve

    (c²/X)(d²X/dx²) = 0

    (1/T)d²T/dt² + w² = 0
     
  4. May 19, 2009 #3

    Shouldn't it be -(c²/X)(d²X/dx²) = 0 ?

    and shouldn't it be equated to a constant?

    How would I go around to get a solution for these equations anyways?
     
  5. May 19, 2009 #4
    yea never mind, you should equate them to some constant

    (c²/X)(d²X/dx²) = k

    (1/T)d²T/dt² + w² = k
     
  6. May 19, 2009 #5

    Cyosis

    User Avatar
    Homework Helper

    Put one variable on one side and the other variable on the other side. For them to be equal they both need to be equal to the same constant! It is not some kind of lame trick to just equate them to a constant. Convince yourself that they must be equal to a constant.
     
  7. May 20, 2009 #6
    Oh ok. So now that I have both equated to the same constant, Do I just integrate both to get a solution or is there a general solution I can deduce from this?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Separation of variables.
  1. Separation of Variables (Replies: 13)

Loading...