I blanked out. Any help is greatly appreciated. Let v(t) be the velocity, in feet per second, of a skydiver at time t seconds, t>0. After her parachute opens, her velocity satisfies the differential equation: dv/dt= -2v-32, with initial condition v(0)=-50. (a) Use separation of variables to find an expression for v in terms of t, where t is measured in seconds. I got up to this far: integral [dv/(-2v-32)]= integral (dt) u= -2v-32; du= -2dv. Help.