- #1

mikiritenshi

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Let v(t) be the velocity, in feet per second, of a skydiver at time t seconds, t>0. After her parachute opens, her velocity satisfies the differential equation: dv/dt= -2v-32, with initial condition v(0)=-50.

(a) Use separation of variables to find an expression for v in terms of t, where t is measured in seconds.

I got up to this far:

integral [dv/(-2v-32)]= integral (dt)

u= -2v-32; du= -2dv.

Help.