(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Seperable Equation

1. Instruction: Solve the equation.

2. Equations:

dy/dx = g(x)p(y)

h(y) = 1/p(y)

h(y)dy = g(x)dx

[tex]\int[/tex]h(y)dy = [tex]\int[/tex]g(x)dx

H(y) = G(x) + C

3. http://img354.imageshack.us/img354/6475/mathdl0.jpg [Broken]

I tried to do it on the right side, but.....I got stuck there. If I add to the right, then I would be left with -C +e[tex]^{-y}[/tex]= ex + -ye[tex]^{-y}[/tex]. Can I say that -C = C? But what aboute[tex]^{-y}[/tex]. Did I inegrate it right?

Thank you in advance.

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# Homework Help: Seperable Equation

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