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Seperate CO2

  1. Mar 19, 2009 #1
    1. The problem statement, all variables and given/known data
    Use the same device to separate singly charged CO2 having 12C and 14C. What are the radii of curvature?

    This is a follow up question based on a HW problem I answered last week. The original problem was this:

    A doubly charged helium atom is accelerated by a voltage 2700V. What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.340-T field?

    2. Relevant equations

    r = mv/qB

    3. The attempt at a solution

    I solved the original problem by saying
    q = 2e for the doubly charged He

    On accelerating through V volts
    1/2mv^2 = qV = (2e)V

    Where v = velocity acquired
    v = squrt(4eV/m) = 2*squrt(eV/m)

    I figured out the mass to be m = 7.26 x 10^-26kg

    And then plugging into the formula.

    Now this new follow up question is throwing me off a little bit. Based on the question asked and info given how would you seperate the CO2? And what would be the charge q of the CO2? Im thinking it would be the 6e from C + 8e(2) of O2 = 22e. Is this correct? Thanks!
  2. jcsd
  3. Mar 19, 2009 #2


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    No it's only the extra charge you put on to isonise it - generally just one e-
  4. Mar 19, 2009 #3
    Oh ok I get it now. Thanks!
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