(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Use the same device to separate singly charged CO_{2}having^{12}C and^{14}C. What are the radii of curvature?

This is a follow up question based on a HW problem I answered last week. The original problem was this:

A doubly charged helium atom is accelerated by a voltage 2700V. What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.340-T field?

2. Relevant equations

r = mv/qB

3. The attempt at a solution

I solved the original problem by saying

q = 2e for the doubly charged He

On accelerating through V volts

1/2mv^2 = qV = (2e)V

Where v = velocity acquired

v = squrt(4eV/m) = 2*squrt(eV/m)

I figured out the mass to be m = 7.26 x 10^-26kg

And then plugging into the formula.

Now this new follow up question is throwing me off a little bit. Based on the question asked and info given how would you seperate the CO_{2}? And what would be the charge q of the CO_{2}? Im thinking it would be the 6e from C + 8e(2) of O2 = 22e. Is this correct? Thanks!

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# Seperate CO2

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