Seperating metals in a solution

  • Thread starter J_o_S
  • Start date
  • #1
18
0
A solution is found to have varying quantities of silver, barium and iron (III) ions.

Suggest a procedure for seperating the ions by precipitation.


Ok ...silver is +1, barium is +2, and iron (III) is +3.... so I would have to add anions of the same value (but negative) to the solution in order to form precipitates.

so for example i could add OH^- and it would form a precipitate with the silver.

I could add CO3^2- and it would form a precipitate with the barium.

And I could add PO4^3- and it would form a precipitate with the iron (III) ions.

This procedure would seperate all the metal ions.

-------------------------------------------------------------------


This is right............ right? :smile:
 

Answers and Replies

  • #2
18
0
anyone?

I'm pretty sure I'm rigght.. but just want to make sure.

thanks
 
  • #3
92
0
Think in terms of solubility products, not oxidation states.
 

Related Threads on Seperating metals in a solution

Replies
7
Views
5K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
2
Replies
26
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
773
Replies
3
Views
843
Replies
5
Views
3K
Replies
1
Views
3K
Top