Seperating metals in a solution (1 Viewer)

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A solution is found to have varying quantities of silver, barium and iron (III) ions.

Suggest a procedure for seperating the ions by precipitation.


Ok ...silver is +1, barium is +2, and iron (III) is +3.... so I would have to add anions of the same value (but negative) to the solution in order to form precipitates.

so for example i could add OH^- and it would form a precipitate with the silver.

I could add CO3^2- and it would form a precipitate with the barium.

And I could add PO4^3- and it would form a precipitate with the iron (III) ions.

This procedure would seperate all the metal ions.

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This is right............ right? :smile:
 
18
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anyone?

I'm pretty sure I'm rigght.. but just want to make sure.

thanks
 
92
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Think in terms of solubility products, not oxidation states.
 

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