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Hello all
For the sequence (n^2 + n -1 )/ (3n^2 +1) I am trying to find
lim (n^2 + n -1)/ (3n^2 +1) = 1/3
n -> 00
My solution"
= 1 - (2n^2 - n +2/ 3n^2 +1) = 1- r(sub-n)
We need to prove that r(sub-n) approaches 2/3.
Hence 2n^2 - n + 2 < 2n^3
3n^2 + 1 > 3n^2
The remainder r sub n is 2n/3. Is this right? How would I find the remainder?
Also how do I find an N such that n > N and the difference between f(x) and L is less than 1/ 10, 1/100, and 1/1000.
Any help would be appreciated.
Thanks
Hello all
For the sequence (n^2 + n -1 )/ (3n^2 +1) I am trying to find
lim (n^2 + n -1)/ (3n^2 +1) = 1/3
n -> 00
My solution"
= 1 - (2n^2 - n +2/ 3n^2 +1) = 1- r(sub-n)
We need to prove that r(sub-n) approaches 2/3.
Hence 2n^2 - n + 2 < 2n^3
3n^2 + 1 > 3n^2
The remainder r sub n is 2n/3. Is this right? How would I find the remainder?
Also how do I find an N such that n > N and the difference between f(x) and L is less than 1/ 10, 1/100, and 1/1000.
Any help would be appreciated.
Thanks