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Sequence of Events

  1. Aug 13, 2012 #1
    Given three characters that have a specific probability assigned to each of them:
    Ω: .2
    θ: .3
    β: .4

    What is the probability of having, say a sequence of 6 of these characters where the first and last character is a θ?
     
  2. jcsd
  3. Aug 13, 2012 #2

    Bacle2

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    First of all: I'm not crazy, Institutions! :)

    Secondly, this is a sort-of rote matter of constructing all sequences:

    θ_ _ _ _ θ

    and then figuring out the probabilities for all of the sequences of this type. I can't

    think of a shortcut.
     
  4. Aug 13, 2012 #3
    glad you got the reference! But not so glad I have to construct a tree to solve this problem...
     
  5. Aug 13, 2012 #4

    Bacle2

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    There may be an alternative: find the probability that neither the first , nor the last

    elements is a θ, so you find the probability of having one of the 4 sequences:

    β_ _ _ _β , β_ _ _ _Ω , Ω _ _ _ _β , Ω _ _ _ _Ω , or maybe less , depending if you

    consider the order does not matter, and then the 2nd and 3rd sequences are the same.
     
  6. Aug 13, 2012 #5
    is it possible then that the answer is (0.3)^2 because the letters in the middle do not really matter? This is just me guessing but if the stuff in the middle doesn't matter then we can simply treat the whole problem as if it were a sequence of two?
     
  7. Aug 13, 2012 #6
    Oh and I made a mistake..those probabilities should add up to 1.
     
  8. Aug 13, 2012 #7

    Bacle2

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    Actually, my bad; I was assuming every event had the same probability. I really

    can't see any option other than considering all the cases separately. Sorry.
     
  9. Aug 14, 2012 #8
    The probability of the sequence is simply [itex](p(\theta))^2[/itex].
     
  10. Aug 14, 2012 #9

    Bacle2

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    Ouch, I think I misread the problem. Sorry.; let me read it again more

    carefully.
     
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