A={xεR:X^11+2X^5<2} let a=supA By choosing a suitable sequence of elements of belonging to A and which tends to a as n->inf, or otherwise, show that a^11+2a^5=<2.Choose another sequence this time of all real numbers not belonging to A to show that a^11+2a^5>=2 and hence show that a^11+2a^5=2,so the equation x^11+2x^5=2 has a real solution(adsbygoogle = window.adsbygoogle || []).push({});

any help would be really appreciated!how can i solve it

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# Sequences and series

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