given the series, determine whether the series converges or diverges:(adsbygoogle = window.adsbygoogle || []).push({});

(E is my sigma)

E sin(4/3n)

Now would it just be the same if i compared 1/n to 3/4n to diverge

Then could I just say since 3/4n diverges then sin(3/4n) must also diverge?

I wouldn't really know how to do the algebra for the direct comparison test or limit comparison test with the sin being there. But i can do the algebra for comparing 1/n with 3/4n..help please

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# Series Converge or Diverge

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