Summing the Series: $\sum (1+2^n)/3^n$

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In summary, the given series can be rewritten as the sum of two geometric series and always converges due to the terms approaching zero. However, the limit of the sequence of terms going to zero is necessary but not sufficient for convergence.
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fsm
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Homework Statement


[tex]\sum (1+2^n)/3^n[/tex]

Find its sum


Homework Equations





The Attempt at a Solution


I don't know how to figure this one out. I took the limit and it was zero so I know it converges. I don't know where to start on this one. The answer is 5/2.
 
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  • #2
Write this as the sum of two summations.
 
  • #3
More precisely, the sum of two geometric series.
 
  • #4
And just because the the terms approach zero, the series always convergent. Think of the harmonic series.
 
  • #5
Typo? I'm quite sure Gib Z meant "just because the terms approach zero, the series is not always convergent". Yes, this particular series converges but your statement " I took the limit (of the sequence of terms) and it was zero so I know it converges" does not follow.
The fact that the limit of the sequence of terms goes to zero is necessary for convergence but not sufficient.
 
  • #6
Typo indeed :( Was in a rush for that post lol.
 

What is the formula for summing the series?

The formula for summing the series is 1 + 2^n / 3^n.

What are the first few terms of the series?

The first few terms of the series are 1, 1 1/3, 1 5/9, 1 13/27, 1 29/81, etc.

What is the pattern in the series?

The pattern in the series is that the numerator increases by powers of 2, while the denominator increases by powers of 3.

What is the limit of the series as n approaches infinity?

The limit of the series as n approaches infinity is 3/2.

How can this series be used in real-life applications?

This series can be used in various fields such as finance, physics, and computer science to calculate compound interest, growth rates, and geometric series. It can also be used in algorithms for data compression and pattern recognition.

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