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Series of questions

  1. Mar 26, 2007 #1
    1. The problem statement, all variables and given/known data

    A horizontal applied force, F, pulls a 21 kg carton across the floor at constant speed. If the coefficient of kinetic friction between the carton and the floor is 0.41, how much work does the applied force do in moving the carton 2.5 m?

    2. Relevant equations

    I'm supposed to be working with energy techniques, we just covered work/power/energy conservation/and so on

    3. The attempt at a solution

    I don't quite understand, it seems to me like the force is 0 given there is no acceleration.
  2. jcsd
  3. Mar 26, 2007 #2

    Doc Al

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    Staff: Mentor

    The fact that there is no acceleration tells you that the net force is zero. Hint: Figure out what the friction force must be and then deduce what F is.
  4. Mar 26, 2007 #3
    That gives way to the problem I have been having in working out a few other problems. I know it's a simple question, but how do I determine normal force (since I'm almost always given the coefficient of kinetic friction)? Is it simply mass times gravity (on a horiztonal surface, at least)?
  5. Mar 26, 2007 #4

    Doc Al

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    Staff: Mentor

    Yes, in this case, the normal force is simply N = mg. In general, you figure it out by setting the sum of the vertical forces equal to zero. The only vertical forces acting on the carton are -mg and +N, so N - mg = 0, and thus N = mg. (Sometimes the applied force will have a vertical component that will affect the normal force.)

    And if the carton were being pushed up an incline instead of on a horizontal surface, you'd figure out the normal force by setting the sum of the forces perpendicular to the incline equal to zero.
  6. Mar 26, 2007 #5
    Thank you very much, that was extremely helpful.
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