find the series for sin(x)/x. I believe this would just mean dividing the series representation of sin(x) by x, therefore sin(x)/x=1-x^2/3!+x^4/5!-x^6/7!.....=sigma(x^2n/(2n+1)!) how then would we find the radius of convergence and interval of convergence. is the series n/sigma(1/k(k+2)) convergent or divergent. I believe the bottom is a telescoping series so it becomes 1/2 so then it becomes 2n and then lim(n-->infinity)=infinity and is therefire divergent. is this correct?