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Series rewrite question

  1. Dec 11, 2011 #1
    Picture of problem included. Just wondering how to get from the first step to the second step?
    Thanks!
     

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  2. jcsd
  3. Dec 11, 2011 #2

    LCKurtz

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    Factor a 4 out of the numerator.
     
  4. Dec 11, 2011 #3
    That leaves me with 4 (1^n/3^n-1) though doesn't it?
     
  5. Dec 11, 2011 #4

    LCKurtz

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    No. What is [itex]4^1\cdot 4^{n-1}[/itex]?
     
  6. Dec 11, 2011 #5
    Oh I see now. Thanks!
     
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