- #1
Hells_Kitchen
- 62
- 0
Find the convergent sum and find the sum of first five terms
[tex]
\sum_{n=1}^{\infty} \frac{sin(nx)}{2^nn}
[/tex] from 1 to infinity.
I have found so far that:
[tex]
\sum_{n=1}^{\infty} \frac{sin(nx)}{2^n} = \frac{2sin(x)}{5-4cos(x)}
[/tex] I am not sure how to consider the [tex]\frac{1}{n}[/tex] term.
Can someone please help?
[tex]
\sum_{n=1}^{\infty} \frac{sin(nx)}{2^nn}
[/tex] from 1 to infinity.
I have found so far that:
[tex]
\sum_{n=1}^{\infty} \frac{sin(nx)}{2^n} = \frac{2sin(x)}{5-4cos(x)}
[/tex] I am not sure how to consider the [tex]\frac{1}{n}[/tex] term.
Can someone please help?
Last edited: