# Series sums

1. Aug 10, 2008

### BoundByAxioms

1. The problem statement, all variables and given/known data
Find the sum of the series: $$\sum^{\infty}_{0}$$(e$$^{\frac{n+1}{n}}-e^{\frac{n+2}{n+1}}$$)

2. Relevant equations
Telescoping series equation.

3. The attempt at a solution
Starting with n=0, I get: (e$$^{2}$$-e$$^{\frac{3}{2}}$$)+(e$$^{\frac{3}{2}}-e^{\frac{4}{3}})+(e^{\frac{n+1}{n}}-e^{\frac{n+2}{n+1}}$$)=e$$^{2}$$ as n approaches infinity. Is this correct?

2. Aug 10, 2008

### rootX

(e^2-e^4/3)
+
(e^4/3 - e^5/4)
+
(e^5/4 - e^6/5)
+
...
+e^(n+1/n - e^(n+2)/(n+1))

=
e^2 - e^(n+2)/(n+1) <-- you forgot this.

And should it be starting with n =1?

3. Aug 10, 2008

### HallsofIvy

Yes, that's a "telescoping" series- every term except the first cancels a later term. Well done.

4. Aug 10, 2008

### BoundByAxioms

Alright! Thanks!