Two resistances R1 and R2, are connected in a series across a 12-V battery. The current increases by .20 A when R2 is removed, leaving R1 connected across the battery. However the current increases by just .10 A when R1 is removed, leaving R2 connected across the battery. Find(a)R1 and (b) R2. V=12v 2. Relevant equations R1+R2=Rs V1+V2=V I=V/R 3. The attempt at a solution I+20= V/R1 I+10= V/R2 I believe the two equations above would give me my answers but I'm stumped on how to go about finding the unknowns. I know V=12 but I can't figure out how find the current or resistances. Can somebody point me in the right direction?