Let (infinity)(sigma)(n=1) = An be a series with positive terms such that lim(n -> infinity) = (An+1)/(An) = L < 1(adsbygoogle = window.adsbygoogle || []).push({});

a) Let L < r < 1. Show that there is an N > 0 such that for all n > N, we have (An+1)/(An) < r

b) Show that Ak+N < or = ANr^k for k = 1, 2....

c) Show that lim (k -> infinity) (Ak+N)^(N+k) < or = r

Thanks!!

For An+1, it's A with sub n+1

An, it's A sub n

Ak+N is A such (k+N)

ANr^k is A sub N times r^k

Thanks!!!!

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# Series with positive terms

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