- #1
Euphoriet
- 105
- 0
I'm trying to find the area for the Koch Snowflake... I can't really figure it out... I found a couple of equations online (I can't really understand how most work.. or how they have been "derived".. including the mathworld one)
I'm looking at the following formula (seems to work.. but I can't figure out the (1-(4/9)^n)/(1-4/9) part.. something to do with an infinite geometric series right?
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Equation:
(sqr(3))/4) + [ ((sqr(3)/12 )) * (1-(4/9)^s)) ] / (1-4/9)
(sorry I could not figure out the pretty print stuff either.)
s = stage of snowflake/fractal, starting from 0
I'm looking at the following formula (seems to work.. but I can't figure out the (1-(4/9)^n)/(1-4/9) part.. something to do with an infinite geometric series right?
---
Equation:
(sqr(3))/4) + [ ((sqr(3)/12 )) * (1-(4/9)^s)) ] / (1-4/9)
(sorry I could not figure out the pretty print stuff either.)
s = stage of snowflake/fractal, starting from 0