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- Thread starter discoverer02
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- #26

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- #27

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The cylinder and box are both 0.25 slug. I have no idea why it's called a slug.

- #28

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I won't use specific numbers since I'm not sure if e.g.

your 8 lbs. is a force or is used as a mass instead of slugs.

Let:

M = mass of cylinder

R = radius of cylinder

I = moment of inertia of cylinder = (MR^2)/2

a = translational acceleration of cylinder and block

T = tension in string

m = mass of block

e = coefficient of friction of block

f = frictional force on block = em

g = acceleration of gravity

We have the following relationships:

Mg - T = Ma (eqn 1)

T - f = ma (eqn 2)

from the rotational motion:

TR = I

rotation is the tension

then TR = ((MR^2)/2)(a/R) = MRa/2

and T = Ma/2 (eqn. 3)

Substituting eqn 3 in eqn 1 we get:

However from substituting in eqn 2 it must also be true that

a = (2m/(M-2m))e

- #29

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Anyway, the correct solution is posted above -- the one headed with "woops" at the middle of page 2.

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