- #1

arvindam

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^{2}: x[tex]\in[/tex]E}. How to prove that set A has measure zero?

(E could be any unbounded subset of R)

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- Thread starter arvindam
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- #1

arvindam

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(E could be any unbounded subset of R)

- #2

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[tex]E\subseteq \bigcup]a_i,b_i[[/tex]

and such that

[tex]\sum{b_i-a_i}<\epsilon[/tex].

Now square the open intervals to obtain an approximation of A.

- #3

arvindam

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- #4

lavinia

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^{2}_{i}-a^{2}i does not have a bound when b_{-}-a_{i}is bounded.

it is easy for any bounded set of measure zero. Split your set up into countably many of these.

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