- #1

libragirl79

- 31

- 0

I let A =(1,2,3...50) and B=(51,52,...100) so there are 25 elememnts of even numbers in each set, multiply them, so there are 625 pairs of (A,B).

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter libragirl79
- Start date

- #1

libragirl79

- 31

- 0

I let A =(1,2,3...50) and B=(51,52,...100) so there are 25 elememnts of even numbers in each set, multiply them, so there are 625 pairs of (A,B).

- #2

clamtrox

- 938

- 9

I let A =(1,2,3...50) and B=(51,52,...100) so there are 25 elememnts of even numbers in each set, multiply them, so there are 625 pairs of (A,B).

No, that's 1 pair: (A,B). Let's think this more carefully. If A = {1,2,3,...,100} = X and B = {1,3,5,...,99}, then what's A*B?

- #3

libragirl79

- 31

- 0

- #4

clamtrox

- 938

- 9

- #5

libragirl79

- 31

- 0

- #6

voko

- 6,054

- 391

You need to think how you could build all the possible A, B pairs that satisfy the condition.

Share:

- Last Post

- Replies
- 6

- Views
- 357

- Replies
- 3

- Views
- 666

- Replies
- 1

- Views
- 511

- Replies
- 6

- Views
- 404

- Replies
- 4

- Views
- 681

- Replies
- 4

- Views
- 269

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 8

- Views
- 537

- Last Post

- Replies
- 2

- Views
- 580

- Replies
- 61

- Views
- 2K