i have to setup a doble integral to find the volume of the solid bounded by the graphs of the equation.(adsbygoogle = window.adsbygoogle || []).push({});

x^2+z^2=1, and y^2+z^2=1

z=sqrt(1-x^2)

z=sqrt(1-y^2)

then substituting in z=sqrt(1-y^2) into x^2+z^2=1, i got y=x.

so when i setup a double integral

for the dy i get integral of(sqrt(1-y^2)) and the limits are from 0-x

and for the limits of he dx i get 0-1.

the way i got the lim its of x was by solving the equation x^2+z^2=1 for x by making z=0, but im not sure if thats right.

and finally when i integrate my double integral, im getting a wrong answer.

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# Homework Help: Setup Double integral

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