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WildFlower

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**The tension in a flat belt pulley is 1250N when stationary. Calculate the tension in each side, and the power transmitted, when the belt is on the point of slipping on the smaller pulley wheel. The wheel is 240mm diameter and the coefficent of friction is 0.320. The angle of lap is 165 degrees and the wheel speed is 1500 RPM.**

If the shaft protrudes from the motor by 100mm., determine a suitable shaft diameter, manufactured from the same material as in question 18 above- the shaft MUST NOT suffer from fatigue at all - that is, it must have an indefinite life span.

If the shaft protrudes from the motor by 100mm., determine a suitable shaft diameter, manufactured from the same material as in question 18 above- the shaft MUST NOT suffer from fatigue at all - that is, it must have an indefinite life span.

The material that is mentioned in the question can be found at htttp://www.specialmetals.com/products/inconelalloyx750.htm and is figure 12.

I have answered the first part of the question and got a power of 20.297 KN and using KSI = Stress/6.894757E-6 I got a value of 268.89MNM2. The tension in each belt came out to be 1788.4 N and 711.6 N.

It is the second part of teh question I have been struggling with. I think I would have to use Bending moments to calculate when the material would fail but even then I would not know what diameter the shaft should be. Plus i'm not totally sure If I have enough information to work out the maximum bending moment.

Could anyone give me any pointers and/or suggest where I'm going wrong and what I should be doing as an alternative.