Torsion in Shafts: Conceptual Doubt Explained

In summary, when studying the stress and strain in power transmission shafts, one end is usually considered fixed while the other receives torque. However, the fixed end is not truly fixed and is only used as a reference point for measuring relative rotation and torque. The purpose of turning a shaft with a motor is to transmit power to a driven machine, requiring torque in the shaft. Treating one end as fixed is simply a way to simplify the problem.
  • #1
ramzerimar
178
23
I have some conceptual doubts about shafts subjected to torsion. When studying Strenght of Materials, to find stress and strain in power transmission shafts, we consider that one of the ends of the shaft is fixed, with all degrees of freedom restricted, and the other one is receiving torque. I'm having trouble to understand this fixed end. If it's a rotating shaft, how can it be fixed? But if it's not fixed, we can't apply equilibrium equations to solve the problem.
 
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  • #2
Suppose that the shaft is strain free (no twist) to begin. Make a mark on each end at the same angular position. Now, twist the shaft so that the angle between the marks is phi. There is now shear stress = T*c/J in the outer fibre, OK?

Now, suppose you roll both ends through an angle theta, maintaining the angular difference phi. The torque in the shaft is the same as it was before because it depends on the relative angle between the ends, not the absolute angle.

Where you choose the reference mark, at theta = 0, theta = pi/27, or something else, it is only the relative rotation, the twist, that matters as far as the induced torque. Treating one end as fixed may be convenient, but it is certainly not necessary.
 
  • #3
Dr.D said:
Suppose that the shaft is strain free (no twist) to begin. Make a mark on each end at the same angular position. Now, twist the shaft so that the angle between the marks is phi. There is now shear stress = T*c/J in the outer fibre, OK?

Now, suppose you roll both ends through an angle theta, maintaining the angular difference phi. The torque in the shaft is the same as it was before because it depends on the relative angle between the ends, not the absolute angle.

Where you choose the reference mark, at theta = 0, theta = pi/27, or something else, it is only the relative rotation, the twist, that matters as far as the induced torque. Treating one end as fixed may be convenient, but it is certainly not necessary.

Suppose I have a shaft supported by a pair of bearings, one at each end, and there's a motor connected to the shaft. When we start the motor, the shaft will rotate with some angular velocity. Why would the shaft twist then, if it is free to rotate because of the bearings?
 
  • #4
If it is truly free to rotate, there will be no torque in the shaft and no shear stress. Why would you do this?

The usual reason for turning a shaft with a motor is to enable the shaft to drive some machine, to do work, and that takes a torque in the shaft to transmit power to the driven machine.
 
  • #5
Dr.D said:
Where you choose the reference mark, at theta = 0, theta = pi/27, or something else, it is only the relative rotation, the twist, that matters as far as the induced torque. Treating one end as fixed may be convenient, but it is certainly not necessary.

Okay. So when I treat one end as fixed is just a way of simplifying things. Actually, it's not really fixed, only in relation to the other end.
 
  • #6
That's about the size of it.
 

1. What is torsion in shafts?

Torsion in shafts refers to the twisting or rotational deformation that occurs when a torque or twisting force is applied to a shaft. This can cause the shaft to twist or bend, and is an important consideration in the design and analysis of mechanical systems.

2. How does torsion affect the strength of a shaft?

Torsion can significantly impact the strength of a shaft. When a torque is applied, it creates shear stresses in the shaft, which can lead to failure if they exceed the material's shear strength. Therefore, it is crucial to consider torsion in the design of shafts to ensure they can withstand the applied forces.

3. What factors influence torsion in shafts?

The amount of torsion experienced by a shaft depends on several factors, including the magnitude and direction of the applied torque, the length and diameter of the shaft, and the material properties of the shaft. Other factors that can influence torsion include the shape and cross-sectional geometry of the shaft.

4. How is torsion in shafts calculated?

The calculation of torsion in shafts involves using the equation T = J * τ, where T is the applied torque, J is the polar moment of inertia, and τ is the shear stress. The polar moment of inertia is a measure of the shaft's resistance to torsion, and it depends on the shaft's cross-sectional geometry. The shear stress can be calculated using the equation τ = T * r / J, where r is the radius of the shaft.

5. How can torsion in shafts be minimized?

Torsion in shafts can be minimized by using materials with high shear strength, increasing the diameter of the shaft, or changing the shaft's cross-sectional shape. Additionally, proper alignment and support of the shaft can help reduce torsion. It is also essential to consider the expected load and torque when designing a shaft to ensure it can withstand the applied forces.

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