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Precalculus Mathematics Homework Help
Sharing a birthday - what's wrong in my approach?
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[QUOTE="Ray Vickson, post: 6061176, member: 330118"] The usual birthday problem looks at more than "pairs"; it asks for the probability that at least two people share a common birthday; perhaps three, or four, or more people share that same birthday. It does so by looking at the probability of no common birthdays, then taking its complement. The problem of computing the probability that exactly one pair share a birthday (and no others do) is much harder. [/QUOTE]
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Precalculus Mathematics Homework Help
Sharing a birthday - what's wrong in my approach?
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