1. The problem statement, all variables and given/known data The Shear modulus for aluminum and copper are 25GPa and 35GPa, respectively. An aluminum and copper pole, both the same length are subjected to the same shear force at the top of each pole, bending each pole a different angle y. Which pole has a higher angle of deflection and by how much? 2. Relevant equations Formulas I am using are Shear Modulus = Shear Stress/Shear Strain S = σ/ε = (F/A)/(Δx/Lo) angle y = ε = Δx/Lo 3. The attempt at a solution Since the forces are equal and area should be equal (under assumption the poles are the same dimensions the shear stress (σ) is equal for both poles. Rearranging the formulas I get σ=S*y σA=σC so 25GPa*yA=38GPa*yC I get that the angle the deflection for the aluminum pole will be 1.52 times that of the copper pole.