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Homework Help: Shear stress of a bolt

  1. Jul 1, 2012 #1
    1. The problem statement, all variables and given/known data

    The material for the bolt shown in the angled joint above has an ultimate tensile strength of 500 MPa and a shear strength of 300 MPa. The diameter of the bolt is 8 mm. Determine the factor of safety in operation.

    2. Relevant equations

    3. The attempt at a solution

    Shear stress= 5,5 . cos 60 (pi . 8 . 2/4)

    = 0.0547kn

    = 54.70 mPA

    Shear Fs= 300/ 54.7 = 5.48

    b) Tensile Stress = 5,5 . sin 60 (pi . 8. 2.4) = 94. 7 Mpa

    Tensile Fs = 500/94.7 5.27

    Is this correct?

    Attached Files:

    • 6m1.jpg
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  2. jcsd
  3. Jul 8, 2012 #2
    You have considered tension and shear independently, but actually they are acting together. To solve, you need to know the shear/tension strength characteristic. The graph of shear stress/ ult shear stress versus tensile stress/ ult tensile stress is sometimes assumed linear, but that is a 'safe' assumption. The experimental results were used to determine at least the relationship for the eurocode and is approximately parabolic or elliptical (I can't remember which without looking it up in ec3)
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