1. Jan 14, 2016 #1

   goldfish9776

   

   1. The problem statement, all variables and given/known data
   for the second photo , why the dy is 0.005/2 ? why not 0.005 ?
   
   2. Relevant equations
   
   
   3. The attempt at a solution

    

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   goldfish9776, Jan 14, 2016
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3. Jan 14, 2016 #2

   haruspex

   

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   Looks like a mistake to me. Also, it says acceleration where it means velocity.

    

   haruspex, Jan 14, 2016
4. Jan 14, 2016 #3

   goldfish9776

   

   In your opinion , it should be 0.005 ???

    

   goldfish9776, Jan 14, 2016
5. Jan 14, 2016 #4

   haruspex

   

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   Yes.

    

   haruspex, Jan 14, 2016

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