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Shear stress problem

  1. Mar 18, 2010 #1
    1. The problem statement, all variables and given/known data

    A steel plate 1m per side and 1cm thick has one edge held in a fixed position. A force F is applied along the upper edge of the plate produces a displacement of 0.005cm. Find the magnitude of F

    2. Relevant equations

    ΔL = (1/G) x (F/A) x (Lo)

    3. The attempt at a solution

    ΔL = 0.005cm = 0.00005m (amount of slip)
    G = 83E09 Pa = 83 000 000 000 Pa = 83E09 N/m2 (shear modulus)
    F = ? (force applied)
    A = 1m x 1m = 1m2 (1 square meter) (area of applied force)
    Lo = 1cm = 0.01m (thickness of material perpendicular to shear force)

    0.00005m = (1/83E09 N/m2) x (F/1m2) x (0.01m)

    F = 4.15E08 = 415 000 000 Nm

    Is this correct?
  2. jcsd
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