Shear stress problem

  • Thread starter Wraith09
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Homework Statement



A steel plate 1m per side and 1cm thick has one edge held in a fixed position. A force F is applied along the upper edge of the plate produces a displacement of 0.005cm. Find the magnitude of F


Homework Equations



ΔL = (1/G) x (F/A) x (Lo)

The Attempt at a Solution



ΔL = 0.005cm = 0.00005m (amount of slip)
G = 83E09 Pa = 83 000 000 000 Pa = 83E09 N/m2 (shear modulus)
F = ? (force applied)
A = 1m x 1m = 1m2 (1 square meter) (area of applied force)
Lo = 1cm = 0.01m (thickness of material perpendicular to shear force)

0.00005m = (1/83E09 N/m2) x (F/1m2) x (0.01m)

F = 4.15E08 = 415 000 000 Nm

Is this correct?
 

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