# Shear Stress

1. Feb 14, 2010

### williamx11373

An inclined member is braced with a glued block, as shown. The ultimate shear stress in the glued joint is 1050 psi. Determine the dimension X at which the glued joint will fail.

I know that

-shearstress= (Pressure x length) dived by (Area x modulus of elasticity)

- At point A there is X forces and Y forces, at point B there is Normal Force.

-Pressure max = (Shearstress X Area)

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so far i know that Force at A in the X direction is 1050x (2x2) = 4200 lbs

other than that im stuck and i dont know where to start.....any help would be appreciated.

2. Feb 14, 2010

### PhanthomJay

wrong equation
yes, assuming the wall is frictionless
max average shear force = max shear stress x Area
Yes, good
What must be the normal force on the ladder from the wall? Then try summing moments about A (must be equal to 0) to solve for X.

3. Dec 9, 2011

### GreenwoodSpur

Is there anyone out there that could help with this problem

4. Dec 10, 2011

### nvn

GreenwoodSpur: Someone did, above, in post 2. Regardless, the PF rules for homework questions state you must list relevant equations yourself, and show your work. And then someone might check your math. (See PF rules link at the top of each page.)