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Shearing MODULUS In PHYSICS

  1. Jan 9, 2012 #1
    1. The problem statement, all variables and given/known data

    How much force is required to punch a hole ½ in. in diameter from a 1/8 in. thick steel sheet of shearing strength 4x10^4 psi.


    2. Relevant equations

    Shearing Modulus = Shearing Stress / Shearing Strain

    Shearing Stress = F/A
    Shearing Strain = S/L

    S = Length Sheared
    L = Length to be sheared

    3. The attempt at a solution
    FIND: FORCE IN lb-f

    Shearing Modulus = Shearing Stress / Shearing Strain

    thus:

    shearing modulus ( shearing strain ) = Shearing Stress

    4x10^4 PSI * ( S/L ) = F/A

    A = ∏/4 (1/2)^2

    (∏/4 (1/2inch)^2)*(4x10^4 PSI)*(S)
    ------------------------------------- = Force
    1/2 inch
    I don't know what S to use because the length sheared(S) is not given.

    Can i still solve the equation without the length sheared(S)?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jan 9, 2012 #2
  4. Jan 11, 2012 #3

    Can you atleast explain to me the relationship of Shearing Strength to this equation and how I can use the value of the Strength of the object to get the force?
     
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