# Homework Help: Shearing MODULUS In PHYSICS

1. Jan 9, 2012

### Myung

1. The problem statement, all variables and given/known data

How much force is required to punch a hole ½ in. in diameter from a 1/8 in. thick steel sheet of shearing strength 4x10^4 psi.

2. Relevant equations

Shearing Modulus = Shearing Stress / Shearing Strain

Shearing Stress = F/A
Shearing Strain = S/L

S = Length Sheared
L = Length to be sheared

3. The attempt at a solution
FIND: FORCE IN lb-f

Shearing Modulus = Shearing Stress / Shearing Strain

thus:

shearing modulus ( shearing strain ) = Shearing Stress

4x10^4 PSI * ( S/L ) = F/A

A = ∏/4 (1/2)^2

(∏/4 (1/2inch)^2)*(4x10^4 PSI)*(S)
------------------------------------- = Force
1/2 inch
I don't know what S to use because the length sheared(S) is not given.

Can i still solve the equation without the length sheared(S)?
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jan 9, 2012

### JaWiB

3. Jan 11, 2012

### Myung

Can you atleast explain to me the relationship of Shearing Strength to this equation and how I can use the value of the Strength of the object to get the force?