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## Homework Statement

51300 kg/hr caustic soda (= 1.115, = 0.349 Btu/lb ∙ ℉ ∙ ft) leaves a dissolver at 190℉ is to be cooled to 120℉ using water at 80℉ which will be heated to 120℉. Knowing that the specific heat and the viscosity at the mean of 0.88 Btu/lb ∙ ℉ and 0.76 cp respectively. Plant practice permits the use of 1.25 in triangular pitch with 1 in OD, 16 ft tube length, 14 BWG. Use a combined dirt factor of 0.002 and pressure drops of 10 psi. Design a suitable heat exchanger.

## Homework Equations

I used the basic design procedure in Lecture 7 B as a guide to design the HE.

## The Attempt at a Solution

Which fluid is the tube side fluid and which is the shell side fluid, if caustic soda is more corrosive than water and it has a smaller flow rate than water?

To estimate the value of the overall heat transfer coefficients for preliminary analysis, what values for the film heat transfer coefficients should I take for the caustic soda if it contains 11 % NaOH and water?

What changes in the design parameters should I consider when redesigning the Shell and tube HE if the calculated length of the tube is larger than the given tube length (6.81 m > 4.87 m)?

New Doc 2018-11-24 04.24.39.pdf Contains images of my attempt at solving the problem