I saw this in an old, junior-level, classical mechanics(adsbygoogle = window.adsbygoogle || []).push({});

textbook and haven't been able to figure it out.

A particle undergoing simple harmonic motion has a velocity:

[tex]\frac{dx_1}{dt}[/tex]

when the displacement is:

[tex]x_1[/tex]

and a velocity

[tex]\frac{dx_2}{dt}[/tex]

when the displacement is:

[tex]x_2[/tex]

What is the angular frequency and the amplitude of the motion in terms of the given quantities?

I know the solution to the SHM wave equation is:

[tex]\begin{equation}

x(t) = A \cdot sin( \omega t + \phi )\end{equation}[/tex]

And that:

[tex]\begin{equation}

dx(t)/dt = A \omega \cdot cos( \omega t + \phi )\end{equation}[/tex]

But can't see how to express omega or A in these terms.

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# SHM Calculus Twister

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