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## Homework Statement

A particle performs S.H.M. with amplitude 25 cm and period 3 s. The minimum time required for it to move between two points 12.5 cm on either side of the mean position is ?

## Homework Equations

##y##=##a## ##sin####w####t##

## The Attempt at a Solution

Solution is

##y##=a sin ##w## t

6.25=25 sin##\frac{2π}{3}##t

t=0.25

I don't understand why would we take y=6.25?

I don't understand what "

__the minimum time required for it to move between two points 12.5 cm on either side of the mean posit____it means?__

**ion is "**I take it as total time required to go from +12.5 to mean position and then from mean position to -12.5 cm.

it will take ##\frac{T}{4}## time to reach +a from mean position i.e to reach 25 cm from mean psition

then it will take T/8 time to reach mean position from +12.5 cm . And it will take another T/8 time to reach -12.5cm from mean position hence total time T/8 + T/8 = 2T/8 = 0.25 T

Right?

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