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**1. Homework Statement**

A block, attached to a spring, moves in Simple Harmonic Motion on a horizontal frictionless

table. The displacement from equilibrium is given by x = xm cos (ω t + φ ) where x is positive to

the right of the equilibrium position. The frequency of the motion is 3.10 Hz and the amplitude

is 15.0 cm. At t = 0.00 s, the velocity of the block is 2.70 m/s to the left and the position is to the

left of the equilibrium position.

Calculate the phase angle, φ.

Answer: 1.96 Rad

I have no Idea what I'm doing wrong. Im almost certain its a stupid mistake

**3. The Attempt at a Solution**

xm=0.15m

w=2[tex]\pi[/tex]f

w=19.478

V=wx

2.7=19.478x

x=0.139

t=0

now I just plugged and chugged it all into x = xm cos (ω t + φ )

but i got the wrong answer...help please