A particle vibrates in SHM with the period of 2.4 s and the amplitude of .1 m.(adsbygoogle = window.adsbygoogle || []).push({});

a) How long is required for the particle to move from one end of its path to the nearest point .05 m from the equilibrium position?

b) What is the particle's speed at this position?

for a) this is what I did

x=Acos(ωt), 5=10cos(ωt), ω=2pi/T=2pi/2.4=2.62

t=arccos(.5)/2.62= 0.4 s

I'm a little confused on part b.

Please see if I did a correctly, and show me how to answer b.

Thanks

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# SHM Question

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