SHM question

  • #1
349
15

Homework Statement


Question is provided

The Attempt at a Solution


The required solution is provided

My question is, the examiner have used sine theta in their expression for change in potential. I keep ending up with 1 - cosine theta
Second question is how did they get rid of theta in the proceeding equation
 

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Answers and Replies

  • #2
35,441
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See the left side. For small angles, ##\sin \theta \approx \theta## and ##\cos \theta \approx 1 - \frac 1 2 \theta^2## (sometimes ##\cos \theta \approx 1## is sufficient).
 

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