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SHM question

  1. Feb 12, 2017 #1
    1. The problem statement, all variables and given/known data
    Question is provided

    3. The attempt at a solution
    The required solution is provided

    My question is, the examiner have used sine theta in their expression for change in potential. I keep ending up with 1 - cosine theta
    Second question is how did they get rid of theta in the proceeding equation

    Attached Files:

  2. jcsd
  3. Feb 12, 2017 #2


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    2017 Award

    Staff: Mentor

    See the left side. For small angles, ##\sin \theta \approx \theta## and ##\cos \theta \approx 1 - \frac 1 2 \theta^2## (sometimes ##\cos \theta \approx 1## is sufficient).
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