SHM - Simple Harmonic Motion

LandOfStandar

SHM - Simple Harmonic Motion Question

1. Homework Statement

Two particles oscillate in SHM along a common straight-line segment of length A. Each particle has a period of 1.5s, but they differ in phase by π/6 rad.
a. How far apart are they 9in terms of A) 0.50s after the lagging particle leaves one end of the path?
b. Are they then moving in the same direction, towards each other, or away from each other?

2. Homework Equations

X = A cos(ωt + θ)
T = 2π/ω

3. The Attempt at a Solution

T = 2π/ω Tω = 2π ω = 2π/T
X = A cos(ωt + θ) = A cos [(2π/T)t + θ] =
A cos [(2π/1.5)t + 0] and A cos [(2π/1.5)t + π/6]
A cos [(2π/1.5)t + 0] - A cos [(2π/1.5)t + π/6], t equals .5s
(-.50)A - (-.87)A = .37A, but the answer in the book is .18A.
What did I do wrong?

Last edited:
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LandOfStandar

Bumping up so someone could tell me what the think.

LandOfStandar

anyone

Just to give the correct answer. Your passages were all good except for the first one. The equations describing the motion of the particles are: (A/2)cos(wt + H) and (A/2)cos(wt) and not just A, because the segment is long A and so (knowing that the cos goes from -1 to + 1) a partile moves from A/2 to -A/2. Substituting A/2 the computation should be right!

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