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SHM - Simple Harmonic Motion Question
Two particles oscillate in SHM along a common straight-line segment of length A. Each particle has a period of 1.5s, but they differ in phase by π/6 rad.
a. How far apart are they 9in terms of A) 0.50s after the lagging particle leaves one end of the path?
b. Are they then moving in the same direction, towards each other, or away from each other?
X = A cos(ωt + θ)
T = 2π/ω
T = 2π/ω Tω = 2π ω = 2π/T
X = A cos(ωt + θ) = A cos [(2π/T)t + θ] =
A cos [(2π/1.5)t + 0] and A cos [(2π/1.5)t + π/6]
A cos [(2π/1.5)t + 0] - A cos [(2π/1.5)t + π/6], t equals .5s
(-.50)A - (-.87)A = .37A, but the answer in the book is .18A.
What did I do wrong?
Homework Statement
Two particles oscillate in SHM along a common straight-line segment of length A. Each particle has a period of 1.5s, but they differ in phase by π/6 rad.
a. How far apart are they 9in terms of A) 0.50s after the lagging particle leaves one end of the path?
b. Are they then moving in the same direction, towards each other, or away from each other?
Homework Equations
X = A cos(ωt + θ)
T = 2π/ω
The Attempt at a Solution
T = 2π/ω Tω = 2π ω = 2π/T
X = A cos(ωt + θ) = A cos [(2π/T)t + θ] =
A cos [(2π/1.5)t + 0] and A cos [(2π/1.5)t + π/6]
A cos [(2π/1.5)t + 0] - A cos [(2π/1.5)t + π/6], t equals .5s
(-.50)A - (-.87)A = .37A, but the answer in the book is .18A.
What did I do wrong?
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